@article{MAKHILLJAVA20121183354,
    title = {Pharmacokinetics of Amikacin after Intravenous Intramuscular and Subcutaneous Administration in German Shepherd Dog},
    journal = {Journal of Animal and Veterinary Advances},
    volume = {11},
    number = {8},
    pages = {1145-1148},
    year = {2012},
    issn = {1680-5593},
    doi = {javaa.2012.1145.1148},
    url = {https://makhillpublications.co/view-article.php?issn=1680-5593&doi=javaa.2012.1145.1148},
    author = {Yongxue Sun,Zhenqing,Yuanqing Lin,Yanying Yu and},
    keywords = {Amikacin,German Shepherd dog,pharmacokinetics,LC-MS/MS,plasma injections,China},
    abstract = {The purpose of the study was to compare the pharmacokinetics of amikacin in German Shepherd dogs following single intravenous intramuscular and subcutaneous injections. Amikacin was administrated by a randomized three cross-over design after single intravenous (10 mg kg<SUP>-1</SUP>) intramuscular (10 mg kg<SUP>-1</SUP>) and subcutaneous injections (10 mg kg<SUP>-1</SUP>) in 9 healthy German Shepherd dogs. The concentrations of Amikacin in plasma were determined by LC-MS/MS and the concentration-time data were analyzed with 3 p97 program. It&#146;s best to fit the amikacin concentration-time data to two-compartment open model after single i.v. dosing. The main pharmacokinetic parameters were as follows: T<SUB>1/2&#946;</SUB> = (1.61&plusmn;0.07) h, V<SUB>c</SUB> = (0.10&plusmn;0.01) L kg<SUP>-1</SUP>, CL<SUB>(s)</SUB> = (0.08&plusmn;0.01) l kg<SUP>-1</SUP> &middot;h, AUC = (129.15&plusmn;6.74) &#956;g mL<SUP>-1</SUP> &middot;h. A two-compartment model with first order absorption best described the drug concentration-time data after single i.m. and s.c. in healthy dogs. The main pharmacokinetic parameters were as follows: T<SUB>1/2&#945;</SUB> = (0.49&plusmn;0.07) h and (0.64&plusmn;0.08) h, respectively; T<SUB>1/2&#946;</SUB> = (1.40&plusmn;0.12) h and (1.78&plusmn;0.15) h, respectively; T<SUB>peak</SUB> = (0.79&plusmn;0.09) h and (0.89&plusmn;0.07) h, respectively; C<SUB>max</SUB> = (44.59&plusmn;2.10) &#956;g mL<SUP>-1</SUP> and (31.42&plusmn;1.39) &#956;g mL<SUP>-1</SUP>, respectively; F = (91.3&plusmn;6.6) and (81.0&plusmn;5.6)%, respectively.}
    }